AND ic.index_column_id = 1

was meant to only look at columns which are first in the index. This should actually be:

AND ic.key_ordinal = 1

So the resulting query is this:

SELECT
s.Name + ‘.’ + t.Name AS TableName
,i.name AS IndexName1
,DupliIDX.name AS DuplicateIndexName
,c.name AS ColumnName
FROM sys.tables AS t
JOIN sys.indexes AS i
ON t.object_id = i.object_id — index belongs to this table
JOIN sys.index_columns ic
ON ic.object_id = i.object_id — columns for this index
AND ic.index_id = i.index_id — index to which column belongs
AND ic.key_ordinal = 1 — only want the first column in the index
JOIN sys.columns AS c
ON c.object_id = ic.object_id
AND c.column_id = ic.column_id — to get the name of the first indexed column
JOIN sys.schemas AS s
ON t.schema_id = s.schema_id
CROSS APPLY
(
SELECT
ind.index_id
,ind.name
FROM sys.indexes AS ind
JOIN sys.index_columns AS ico
ON ico.object_id = ind.object_id
AND ico.index_id = ind.index_id
AND ico.key_ordinal = 1
WHERE ind.object_id = i.object_id
AND ind.index_id > i.index_id — exclude the clustered index (which is the PK usually)
AND ico.column_id = ic.column_id
) DupliIDX
ORDER BY
s.name,t.name,i.index_id,c.column_id
GO

Nice article to start with finding out duplicate indexes.
But after reading this article , there were some questions popped up in my mind.

IndexA(Column1,Column2)
IndexB(Column1,Column2,Column3,Column4,Column5)
IndexC(Column2,Column3)
IndexD(Column1,Column3)
IndexE(Column1,Column4)

After completing this article , i am thinking that the duplicate indexe is IndexA.
But in your example , you have mentioned that IndexD ,IndexE along with IndexA are redundant.

Please reply.

Thanks in Advance.