Comments on: SQL Server Interview: Advance SQL Query – Find a count of repeated character in a String https://www.dbrnd.com/2017/06/sql-server-interview-advance-sql-query-find-a-count-of-repeated-character-in-a-string/ BIGData | NoSQL | MSSQL | MySQL | PostgreSQL Mon, 01 Oct 2018 09:18:04 +0000 hourly 1 https://wordpress.org/?v=7.0.4 By: Ankush https://www.dbrnd.com/2017/06/sql-server-interview-advance-sql-query-find-a-count-of-repeated-character-in-a-string/#comment-6729 Mon, 01 Oct 2018 09:18:04 +0000 https://www.dbrnd.com/?p=5354#comment-6729 select coalesce(length(‘INDIA’) – length(replace(‘INDIA’,’A’,null)), length(‘INDIA’), 0)
from dual;

]]> By: Sai Reddy https://www.dbrnd.com/2017/06/sql-server-interview-advance-sql-query-find-a-count-of-repeated-character-in-a-string/#comment-6510 Tue, 03 Jul 2018 08:27:59 +0000 https://www.dbrnd.com/?p=5354#comment-6510 select name,len(name)-len(replace(name,’a’,”)) from tbl_Strings

]]> By: Anvesh Patel https://www.dbrnd.com/2017/06/sql-server-interview-advance-sql-query-find-a-count-of-repeated-character-in-a-string/#comment-6041 Sun, 26 Nov 2017 18:03:37 +0000 https://www.dbrnd.com/?p=5354#comment-6041 Sure, you can also share your solution here

]]> By: Hemanth Sharma https://www.dbrnd.com/2017/06/sql-server-interview-advance-sql-query-find-a-count-of-repeated-character-in-a-string/#comment-6038 Sat, 25 Nov 2017 11:58:02 +0000 https://www.dbrnd.com/?p=5354#comment-6038 In the above query why we need to use “ASCII(Letter) AS CharAsciiCode” in the select statement?
I tried without using that and got the output with no capital letters

For Eg: India
& output is like —– n 1 , d 1 , i 1 , a 1

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