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	Comments on: SQL Puzzle: SQL Advance Query &#8211; Find count of value from multiple columns	</title>
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	<description>BIGData &#124; NoSQL &#124; MSSQL &#124; MySQL &#124; PostgreSQL</description>
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		<title>
		By: eswaraiah.kuna		</title>
		<link>https://www.dbrnd.com/2017/10/sql-puzzle-sql-advance-query-find-count-of-value-from-multiple-columns/#comment-6506</link>

		<dc:creator><![CDATA[eswaraiah.kuna]]></dc:creator>
		<pubDate>Fri, 29 Jun 2018 05:54:53 +0000</pubDate>
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					<description><![CDATA[SELECT tag, COUNT(tag)as valucount FROM GroupColumns 
where Val1 like &#039;a&#039; or Val2 like &#039;a&#039;
group by tag
having COUNT(tag)&#062;=1]]></description>
			<content:encoded><![CDATA[<p>SELECT tag, COUNT(tag)as valucount FROM GroupColumns<br />
where Val1 like &#8216;a&#8217; or Val2 like &#8216;a&#8217;<br />
group by tag<br />
having COUNT(tag)&gt;=1</p>
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		<title>
		By: Dinesh.IS		</title>
		<link>https://www.dbrnd.com/2017/10/sql-puzzle-sql-advance-query-find-count-of-value-from-multiple-columns/#comment-5930</link>

		<dc:creator><![CDATA[Dinesh.IS]]></dc:creator>
		<pubDate>Mon, 16 Oct 2017 08:16:41 +0000</pubDate>
		<guid isPermaLink="false">https://www.dbrnd.com/?p=5775#comment-5930</guid>

					<description><![CDATA[Select Tag,Count(Val1) As NoOfValues From GroupColumns Where Val1=&#039;A&#039;
Group By Tag
Union All
Select Tag,Count(Val2) From GroupColumns Where Val2=&#039;A&#039;
Group By Tag]]></description>
			<content:encoded><![CDATA[<p>Select Tag,Count(Val1) As NoOfValues From GroupColumns Where Val1=&#8217;A&#8217;<br />
Group By Tag<br />
Union All<br />
Select Tag,Count(Val2) From GroupColumns Where Val2=&#8217;A&#8217;<br />
Group By Tag</p>
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