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	<title>
	Comments on: SQL Puzzle: SQL Advance Query &#8211; Find date range for same Market Rank	</title>
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	<link>https://www.dbrnd.com/2017/10/sql-puzzle-sql-advance-query-find-date-range-for-same-market-rank/</link>
	<description>BIGData &#124; NoSQL &#124; MSSQL &#124; MySQL &#124; PostgreSQL</description>
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		<title>
		By: Lakshman		</title>
		<link>https://www.dbrnd.com/2017/10/sql-puzzle-sql-advance-query-find-date-range-for-same-market-rank/#comment-7046</link>

		<dc:creator><![CDATA[Lakshman]]></dc:creator>
		<pubDate>Sat, 27 Apr 2019 16:19:52 +0000</pubDate>
		<guid isPermaLink="false">https://www.dbrnd.com/?p=5782#comment-7046</guid>

					<description><![CDATA[SELECT MIN(RankDate) AS StartDate,MAX(RankDate) AS EndDate,RankNo
FROM MarketRank
GROUP BY RankNo]]></description>
			<content:encoded><![CDATA[<p>SELECT MIN(RankDate) AS StartDate,MAX(RankDate) AS EndDate,RankNo<br />
FROM MarketRank<br />
GROUP BY RankNo</p>
]]></content:encoded>
		
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		<title>
		By: Dinesh.IS		</title>
		<link>https://www.dbrnd.com/2017/10/sql-puzzle-sql-advance-query-find-date-range-for-same-market-rank/#comment-5986</link>

		<dc:creator><![CDATA[Dinesh.IS]]></dc:creator>
		<pubDate>Tue, 07 Nov 2017 05:08:21 +0000</pubDate>
		<guid isPermaLink="false">https://www.dbrnd.com/?p=5782#comment-5986</guid>

					<description><![CDATA[--Method-1
Select Min(RankDate) As StartDate,Max(RankDate) As EndDate,B.RankNo  
From MarketRank  A 
Inner JOin (Select Distinct RankNo 
From MarketRank) B On A.rankno=B.rankno
Group By B.RankNo 

--Method-2
Select Min(RankDate) As StartDate,Max(RankDate) As EndDate,RankNo 
From (Select RankDate,RankNo 
From MarketRank )  A 
Group By RankNo]]></description>
			<content:encoded><![CDATA[<p>&#8211;Method-1<br />
Select Min(RankDate) As StartDate,Max(RankDate) As EndDate,B.RankNo<br />
From MarketRank  A<br />
Inner JOin (Select Distinct RankNo<br />
From MarketRank) B On A.rankno=B.rankno<br />
Group By B.RankNo </p>
<p>&#8211;Method-2<br />
Select Min(RankDate) As StartDate,Max(RankDate) As EndDate,RankNo<br />
From (Select RankDate,RankNo<br />
From MarketRank )  A<br />
Group By RankNo</p>
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