Comments on: SQL Puzzle: SQL Advance Query – Find the average shared salary by each department

By: ANIL

ANIL — Thu, 01 Aug 2019 10:56:16 +0000

SELECT DEPTID,DEPTSAL,TOTSAL,(DEPTSAL*100/TOTSAL)AS PER
FROM

(SELECT DEPTID,SUM(SALARY)AS DEPTSAL,
(SELECT SUM(A.SALARY) AS TOTSAL FROM TBL_EMP A WHERE A.DEPTID=DEPTID) AS TOTSAL

FROM TBL_EMP GROUP BY DEPTID ORDER BY DEPTID) AS F

By: Lakshman

Lakshman — Sat, 27 Apr 2019 05:37:26 +0000

SELECT distinct DeptId,SUM(Salary) OVER (PARTITION BY DeptId) AS DeptTotalSalary,SUM(Salary) over () AS AllTotal
,SUM(Salary) OVER (PARTITION BY DeptId)*100/SUM(Salary) over () AS SharedPercentage
from tbl_emp

By: Ankush

Ankush — Mon, 01 Oct 2018 06:54:03 +0000

Select dept_id, DeptTotalSalary, AllTotal ,ROUND((DeptTotalSalary*100)/AllTotal,3) as percent from (Select foo.emp_id, foo.emp_name, foo.dept_id, foo.salary, foo2.AllTotal,DeptTotalSalary from tbl_Emp foo
CROSS JOIN
(select sum(salary) as AllTotal from tbl_Emp )foo2
JOIN
(Select sum(salary) as DeptTotalSalary, dept_id from tbl_Emp group by dept_id) foo3 ON foo.dept_id = foo3.dept_id) foo4
group by dept_id, DeptTotalSalary, AllTotal

By: Dinesh.IS

Dinesh.IS — Wed, 25 Oct 2017 05:28:12 +0000

Declare @Total As Numeric(19,2);
Select @Total=Sum(IsNull(Salary,0)) From TBL_EMP
Select DeptID,Sum(IsNull(Salary,0)) As Salary,@Total As AllTotal,Floor(((Sum(IsNull(Salary,0))/IsNull(@Total,0))*100)) As SharedPercentage
From tbl_Emp
Group By DeptID