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	<title>
	Comments on: SQL Puzzle: SQL Advance Query &#8211; Use STUFF() and form the aggregate of columns	</title>
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	<description>BIGData &#124; NoSQL &#124; MSSQL &#124; MySQL &#124; PostgreSQL</description>
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		<title>
		By: Dinesh.IS		</title>
		<link>https://www.dbrnd.com/2017/10/sql-puzzle-sql-advance-query-use-stuff-and-form-the-aggregate-of-columns/#comment-5951</link>

		<dc:creator><![CDATA[Dinesh.IS]]></dc:creator>
		<pubDate>Tue, 24 Oct 2017 04:05:32 +0000</pubDate>
		<guid isPermaLink="false">https://www.dbrnd.com/?p=5841#comment-5951</guid>

					<description><![CDATA[;
WITH CTE
As
(Select Distinct CarName
From Cars)
Select CarName,STUFF((Select &#039;,&#039;+&#039; Rout: &#039;+Rout+  &#039;,Driven By  &#039;+Cast(Driver As VarChar(Max))+  &#039;  In Year  &#039;+Convert(VarChar(Max),Year)
From Cars A Where A.CarName=B.CarName For XML PATH(&#039;&#039;)),1,2,&#039;&#039;) As DrivenDetails
From CTE B]]></description>
			<content:encoded><![CDATA[<p>;<br />
WITH CTE<br />
As<br />
(Select Distinct CarName<br />
From Cars)<br />
Select CarName,STUFF((Select &#8216;,&#8217;+&#8217; Rout: &#8216;+Rout+  &#8216;,Driven By  &#8216;+Cast(Driver As VarChar(Max))+  &#8216;  In Year  &#8216;+Convert(VarChar(Max),Year)<br />
From Cars A Where A.CarName=B.CarName For XML PATH(&#8221;)),1,2,&#8221;) As DrivenDetails<br />
From CTE B</p>
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