Comments on: SQL Puzzle: SQL Advance Query – Find Employee with salary greater than their Manager

By: Marcel Hofman

Marcel Hofman — Thu, 21 Mar 2019 15:10:41 +0000

SELECT * FROM empsalary
WHERE managerid IS NOT NULL AND empsalary > (SELECT MAX(empsalary) FROM empsalary WHERE managerid IS NULL)

By: Anvesh Patel

Anvesh Patel — Sun, 28 Jan 2018 19:17:17 +0000

In reply to Janet. The filter that you applied inside the subquery which is not returning any data. I modified your query, select * from empsalary as e where e.empsalary > (select e1.empsalary from empsalary as e1 where e.ManagerID = e1.EmpID )

By: Janet

Janet — Sun, 28 Jan 2018 19:10:48 +0000

Yes, it is working, but mine is not working and I’m trying to understand why it is not. Thank you.

By: Anvesh Patel

Anvesh Patel — Sun, 28 Jan 2018 19:08:56 +0000

In reply to Janet. Your alternative solution (correlated subquery ) is similar to Shamanth, please try the solution given by him. Select * From Empsalary E Where E.EmpSalary > (Select E1.Empsalary From Empsalary E1 Where E.ManagerID=E1.EmpID)

By: Janet

Janet — Sun, 28 Jan 2018 18:57:29 +0000

Why my query does not work?

select * from empsalary as e
where e.empsalary=(select e1.empsalary from empsalary as e1 where e.EmpID = e1.ManagerID and e1.EmpSalary > e.EmpSalary)

It’s result is null. What is the correct format if I want to use subquery? Thank you

By: Shamanth

Shamanth — Thu, 30 Nov 2017 12:10:44 +0000

Using Sub-Query:

Select * From Empsalary E
Where E.EmpSalary >
(Select E1.Empsalary From Empsalary E1
Where E.ManagerID=E1.EmpID)