By: Dpan

Dpan — Tue, 23 Apr 2019 11:43:11 +0000

DECLARE @str AS VARCHAR(100) = ‘I am Anvesh Patel, owner @str DBRND.COM’,@i as int=1,@lengthOfstr as int,@getString as nvarchar(max),
@sumOfUpper as int,@sumOfLower as int,@sumOfOtherChar as int
set @lengthOfstr=LEN(@str);set @sumOfUpper=0;set @sumOfLower=0;set @sumOfOtherChar=0;
while (@i<=@lengthOfstr)
begin
select @getString= SUBSTRING(@str,@i,1)
select @sumOfUpper+=case when ASCII(@getString) between 65 and 90 then 1 else 0 end;
select @sumOfLower+=case when ASCII(@getString) between 97 and 122 then 1 else 0 end;
select @sumOfOtherChar+=case when (ASCII(@getString) not between 65 and 90 and ASCII(@getString) not between 97 and 122) then 1 else 0 end;
set @i=@i+1;

end
print (Concat('Upper char–', @sumOfUpper))
print (Concat('Lower char–', @sumOfLower))
print (Concat('Other char–', @sumOfOtherChar))

Comments on: SQL Puzzle: SQL Advance Query – Find the count of Lowercase, Uppercase, Special Characters

By: Dpan