Comments on: SQL Puzzle: SQL Advance Query – Reduce duplicate column data by merging ID with it

By: Satish Kumar

Satish Kumar — Mon, 06 Apr 2020 08:41:22 +0000

SELECT
T1.ID,
COALESCE(X.NAME+CAST(X.RN AS VARCHAR(10)),T1.NAME) AS [NAME]
FROM
#tbl_DuplicateString T1
LEFT JOIN
(
SELECT
*
FROM
(
SELECT
ID,NAME,
ROW_NUMBER()over(partition by name order by id) AS RN,
COUNT(1) OVER(PARTITION BY NAME) CNT
FROM
#tbl_DuplicateString

) Y
WHERE
CNT >1

) X ON T1.ID = X.ID

By: Satish Kumar

Satish Kumar — Mon, 06 Apr 2020 08:39:31 +0000

SELECT
T1.ID,COALESCE(X.NAME+CAST(X.RN AS VARCHAR(10)),T1.NAME) AS [NAME]
FROM
#tbl_DuplicateString T1
LEFT JOIN
(
SELECT
*
FROM
(
select
ID,NAME,
ROW_NUMBER()over(partition by name order by id) AS RN,
COUNT(1) OVER(PARTITION BY NAME) CNT
from
#tbl_DuplicateString
GROUP BY ID,NAME
) Y
WHERE
CNT >1

) X ON T1.ID = X.ID

By: Marcel Hofman

Marcel Hofman — Tue, 26 Mar 2019 10:17:33 +0000

with cte as
(
select *, ROW_NUMBER () OVER (partition by name ORDER BY ID) AS duplicates from tbl_DuplicateString
)
select case when duplicates = 1 then name
ELSE name + CAST(duplicates AS VARCHAR(10))
END AS name FROM cte

By: Pree

Pree — Sat, 25 Aug 2018 13:26:04 +0000

select id
, case when n1.count >1 then t.name || t.ID
else t.name end as Name
from tbl_DuplicateString t
left join (select name
, count(*)
from tbl_DuplicateString
group by name) n1 on t.name = n1.name

By: Dinesh.IS

Dinesh.IS — Tue, 07 Nov 2017 07:25:07 +0000

;
WITH CTE
As
(Select Row_Number()Over(Partition By Name Order By Name) As SLNo,* From tbl_DuplicateString)
Select ID,(Case When NoOfCnt>1 Then A.Name+Convert(VarChar(2),SLNo) Else A.Name End) As Name From CTE A
Inner Join (Select Name,Count(*) As NoOfCnt
From CTE
Group By Name) B On B.Name=A.Name