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	Comments on: SQL Puzzle: SQL Advance Query – Find last SET of String after Specific character	</title>
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	<link>https://www.dbrnd.com/2018/02/sql-puzzle-find-last-set-of-string-after-specific-character/</link>
	<description>BIGData &#124; NoSQL &#124; MSSQL &#124; MySQL &#124; PostgreSQL</description>
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		<title>
		By: sp		</title>
		<link>https://www.dbrnd.com/2018/02/sql-puzzle-find-last-set-of-string-after-specific-character/#comment-6945</link>

		<dc:creator><![CDATA[sp]]></dc:creator>
		<pubDate>Wed, 03 Apr 2019 07:17:30 +0000</pubDate>
		<guid isPermaLink="false">https://www.dbrnd.com/?p=7168#comment-6945</guid>

					<description><![CDATA[Select SUBSTR(&#039;rerc-poiq-xxxx&#039; ,instr(&#039;rerc-poiq-xxxx&#039;,&#039;-&#039;,1,2)+1) from dual]]></description>
			<content:encoded><![CDATA[<p>Select SUBSTR(&#8216;rerc-poiq-xxxx&#8217; ,instr(&#8216;rerc-poiq-xxxx&#8217;,&#8217;-&#8216;,1,2)+1) from dual</p>
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		<item>
		<title>
		By: Ankush		</title>
		<link>https://www.dbrnd.com/2018/02/sql-puzzle-find-last-set-of-string-after-specific-character/#comment-6694</link>

		<dc:creator><![CDATA[Ankush]]></dc:creator>
		<pubDate>Fri, 14 Sep 2018 07:47:43 +0000</pubDate>
		<guid isPermaLink="false">https://www.dbrnd.com/?p=7168#comment-6694</guid>

					<description><![CDATA[In Oracle :

Select SUBSTR(&#039;abddcd-nboib-xxxexxx&#039; , -INSTR(REVERSE(&#039;abddcd-nboib-xxxexxx&#039;),&#039;-&#039;)+1) from dual]]></description>
			<content:encoded><![CDATA[<p>In Oracle :</p>
<p>Select SUBSTR(&#8216;abddcd-nboib-xxxexxx&#8217; , -INSTR(REVERSE(&#8216;abddcd-nboib-xxxexxx&#8217;),&#8217;-&#8216;)+1) from dual</p>
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