Comments on: SQL Puzzle: Generate Calendar Data for 19th Century

By: HIC

HIC — Tue, 16 Apr 2019 10:09:39 +0000

WITH calendar(fdate) AS (
SELECT to_date(‘01.01.1900’, ‘dd.mm.yyyy’) as fdate from dual
UNION ALL
SELECT fdate + 1 FROM calendar
WHERE fdate + 1 <= sysdate
)
SELECT fdate FROM calendar;

By: Kati Novikov

Kati Novikov — Tue, 12 Feb 2019 18:04:15 +0000

declare @dt date = ‘1900-01-01’
create table #date (dt date);

while @dt < getdate()
begin
insert into #date (dt) values (@dt);
set @dt = DATEADD(day, 1, @dt);
end

select * from #date

By: Ovidiu-Ionel Samfirescu

Ovidiu-Ionel Samfirescu — Mon, 14 Jan 2019 20:45:35 +0000

DECLARE @INPUTDATE INT = 19000101
DECLARE @TABLE TABLE (CalendarDATE DATE)
INSERT INTO @TABLE
SELECT CAST(SUBSTRING(CAST(@INPUTDATE AS CHAR),1,4) + ‘-‘ + SUBSTRING(CAST(@INPUTDATE AS CHAR),5,2) + ‘-‘ + SUBSTRING(CAST(@INPUTDATE AS CHAR),7,8) AS DATE)
WHILE (SELECT MAX(CalendarDATE) FROM @TABLE) < '2001-01-01'
BEGIN
INSERT INTO @TABLE
SELECT DATEADD(DAY,1,(SELECT MAX(CalendarDATE) FROM @TABLE))
DECLARE @PRINT NVARCHAR(100) = (SELECT CAST(MAX(CalendarDATE) AS NVARCHAR) FROM @TABLE)
PRINT @PRINT
END
SELECT * FROM @TABLE