Comments on: SQL Puzzle: Get the list of Monday of a Month

By: Keith Fernandes

Keith Fernandes — Sun, 27 Oct 2019 14:17:34 +0000

declare @start date = ‘2018-04-01’
declare @end date = ‘2018-04-30’
;with cte as
(
select @start as date
union all
select DATEADD(DAY,1,date) as date1 from cte
where DATEADD(DAY,1,date) <= @end
)
select * from cte where DATENAME(DW,date) = 'Monday'

By: HIC

HIC — Sat, 27 Apr 2019 13:48:54 +0000

WITH days(mon) AS (
SELECT next_day(to_date(‘31.03.2018’, ‘dd.mm.yyyy’), ‘monday’) as mon from dual
UNION ALL
SELECT mon + 7 FROM days
WHERE mon + 7 <= to_date('01.05.2018', 'dd.mm.yyyy')
)
SELECT * FROM days;

By: Dpan

Dpan — Mon, 15 Apr 2019 09:27:26 +0000

declare @dateOfApril date,@dayOfApril nvarchar(max)
set @dateOfApril=’2018-04-01′;
While (@dateOfApril<'2018-05-01')
begin
set @dayOfApril=DATENAME(dw,@dateOfApril)
if(@dayOfApril='Monday')
Begin
print @dateOfApril;
End
set @dateOfApril=DateAdd(dd,1,@dateOfApril);
end

By: VINUTNA

VINUTNA — Sun, 06 May 2018 14:47:39 +0000

declare @x date = ’04-01-2018′
while (@x <= '04-30-2018')
begin
select @x=dateadd(day,1,@x)
if datepart(dw,@x)=2
begin
select @x
end
end