Comments on: SQL Puzzle: Find Correlation Coefficients for the Run of Cricket Players https://www.dbrnd.com/2018/07/sql-puzzle-find-correlation-coefficients-for-the-run-of-cricket-players/ BIGData | NoSQL | MSSQL | MySQL | PostgreSQL Tue, 23 Oct 2018 17:59:47 +0000 hourly 1 https://wordpress.org/?v=7.0.6 By: abraham https://www.dbrnd.com/2018/07/sql-puzzle-find-correlation-coefficients-for-the-run-of-cricket-players/#comment-6764 Tue, 23 Oct 2018 17:59:47 +0000 https://www.dbrnd.com/?p=7509#comment-6764 with avg_tbl as(
select avg(runs) a, playername from tbl_players group by playername
),
cte as (
select playername, runs, matchyear, row_number() over (partition by matchyear order by playername) r from tbl_players
),
cte2 as (
select tb.playername, tb.runs ru1, tb.matchyear,p,ru ru2,av.a a1,av2.a a2, tb.runs-av.a a , ru-av2.a b,
(tb.runs-av.a)*( ru-av2.a) axb,(tb.runs-av.a)*(tb.runs-av.a) asquared, ( ru-av2.a)*( ru-av2.a) bsquared from cte as tb
cross apply (select playername p, runs ru, r from cte
where matchyear=tb.matchyear and playername tb.playername and r>tb.r ) as v

join avg_tbl av on av.playername= tb.playername
join avg_tbl av2 on av2.playername= p
) select sum(axb),sum(asquared), sum(bsquared), sum(axb)/(sqrt(sum(asquared))*sqrt(sum(bsquared))) from cte2 group by playername,p

]]> By: Anvesh Patel https://www.dbrnd.com/2018/07/sql-puzzle-find-correlation-coefficients-for-the-run-of-cricket-players/#comment-6517 Wed, 04 Jul 2018 18:03:45 +0000 https://www.dbrnd.com/?p=7509#comment-6517 Sure, will help you. You can share more detail via contact me page and I will get back to you.

]]> By: dinesh danny https://www.dbrnd.com/2018/07/sql-puzzle-find-correlation-coefficients-for-the-run-of-cricket-players/#comment-6514 Wed, 04 Jul 2018 04:57:13 +0000 https://www.dbrnd.com/?p=7509#comment-6514 Hi sir,
I had seen your sql puzzle. really its very interesting. And more thing i need to learn Postgresql administration part can you please explain and post postgres.conf file information, vacuum analyze, MVCC concepts, replication concepts and all concepts.
Because the way of explaining topics is very clear and very easy to understand. Can you please me.

regards,
Dinesh.A

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