Comments on: SQL Puzzle: SQL Advance Query – Check a String Is Number or Not

By: Nikhil Bhosale

Nikhil Bhosale — Wed, 14 Aug 2019 09:20:38 +0000

Declare @str nvarchar(100) = ‘8424ij9694’;

if(Isnumeric(@str) = 1)
begin
Select ‘Given string is Numeric !’ AS Result
end
else
begin
Select ‘Given string is not a Numeric !’ AS Result
end

By: Dinesh

Dinesh — Tue, 06 Nov 2018 07:49:08 +0000

if we use the “E” validating is missing.

DECLARE @str NVARCHAR(100) = ‘888E’
IF(ISNUMERIC(@str) = 1)
BEGIN
PRINT ‘Yes Numeric’
END
ELSE
BEGIN
PRINT ‘Not Numeric’
END

DECLARE @str NVARCHAR(100) = ’88E’
IF((IsNumeric(@Str)=1 And PatIndex(‘%[a-z A-Z]%’,@Str)<=0))
BEGIN
PRINT 'Yes Numeric'
END
ELSE
BEGIN
PRINT 'Not Numeric'
END

By: Dinesh

Dinesh — Tue, 06 Nov 2018 07:45:31 +0000

If used special character your statement is given wrong result.

DECLARE @str VARCHAR(50)
SET @str =’8-‘;
SELECT CASE WHEN @str NOT LIKE ‘%[^0-9.-]%’
THEN ‘Yes Numeric’ ELSE ‘Not Numeric’ END IsNumber

GO
Declare @Str As VarChar(50)
Set @Str=’8-‘
Select (Case When (PatIndex(‘%[^0-9%’,@Str)>0 Or PatIndex(‘%[~`!@#$%^&*()-_=+ a-z A-Z]%’,@Str)>0) Then ‘Not Numeric’ Else ‘Yes Numeric’ End)