Comments on: SQL Puzzle: SQL Advance Query – Generate the data in the RANGE format

By: Hareesh

Hareesh — Fri, 03 Jan 2020 10:23:27 +0000

with CTE as (select 0 as Val
union
select Val from Ranges)
select Val as [Lower Range], LEAD(Val) over (order by val) as [Upper Range] from CTE

By: sohail

sohail — Sat, 02 Nov 2019 06:38:09 +0000

select val , LEAD(val) over (order by val)
from
(select 0 as val union select val from Ranges ) as t

By: koustav modak

koustav modak — Wed, 30 Oct 2019 12:46:06 +0000

(select a1.val LowerRange ,a2.val UpperRange from
(select row_number() over() as rnk,a.* from
(select * from
(select 0 val from Ranges
union
select Val from Ranges)T
order by 1)a )a1,
(select row_number() over() as rnk,a.* from
(select * from
(select 0 val from Ranges
union
select Val from Ranges)T
order by 1)a )a2
where a1.rnk+1=a2.rnk)
union all
(select Val,null from Ranges order by 1 desc limit 1)

By: Sai Nath

Sai Nath — Sun, 11 Aug 2019 08:13:13 +0000

; WITH CTE AS
(
SELECT
*,
ROW_NUMBER() OVER( ORDER BY (SELECT 1)) AS RW
FROM
Ranges
)

SELECT
A.VAL,
B.VAL
FROM
CTE AS A
LEFT JOIN
CTE AS B ON A.RW = B.RW-1

UNION

SELECT
B.VAL,
A.VAL
FROM
CTE AS A
LEFT JOIN
CTE AS B ON A.RW-1 = B.RW

By: HIC

HIC — Sat, 06 Apr 2019 19:58:58 +0000

with a as (
select rownum as id, val
from ranges
)
, b as (
select (rownum + 1) as id, val
from ranges
)
select nvl(b.val, 0) as LowerRange, a.val as UpperRange
from a
full join b on b.id = a.id
order by LowerRange;