Check the below input data and require output data to find maximum consecutive wins for team India.

Input Data:

TeamOne TeamTwo MatchDate  WonBy
------- ------- ---------- -----
Ind     Aus     2017-08-22 Ind
Ind     Aus     2016-08-26 Ind
Ind     Aus     2014-08-14 Ind
Ind     Aus     2013-08-23 Aus
Ind     Aus     2012-08-25 Ind
Ind     Aus     2010-08-08 Ind

Expected output:

TeamOne TeamTwo MatchDate  WonBy
------- ------- ---------- -----
Ind     Aus     2014-08-14 Ind
Ind     Aus     2012-08-25 Ind
Ind     Aus     2010-08-08 Ind

Create a table with sample data:

CREATE TABLE Matches
(
	TeamOne CHAR(3)
	,TeamTwo CHAR(3)
	,MatchDate DATE
	,WonBy CHAR(3)
)
GO
 
INSERT INTO Matches
VALUES
('Ind','Aus','08-22-2017','Ind')
,('Ind','Aus','08-26-2016','Ind')
,('Ind','Aus','08-14-2014','Ind')
,('Ind','Aus','08-23-2013','Aus')
,('Ind','Aus','08-25-2012','Ind')
,('Ind','Aus','08-08-2010','Ind')
GO

Solution:

;WITH CTE AS
(
	SELECT TeamOne,TeamTwo,MatchDate,WonBy         
	,ISNULL(Lead(WonBy) OVER (ORDER BY (SELECT NULL)),0) AS NextWin
	FROM Matches
)
,CTE2 AS
(
	SELECT *,IIF(NextWin<> WonBy,1,0) AS a
	,ROW_NUMBER() OVER( ORDER BY (SELECT NULL)) AS b
	FROM cte
)
,CTE3 AS
(
    SELECT *, b - ISNULL(lag(b) OVER (ORDER BY (SELECT NULL)),0) AS C 
	FROM CTE2
    WHERE a = 1
)
SELECT t2.* FROM cte3 t1
RIGHT OUTER JOIN Matches t2 ON t1.MatchDate = t2.MatchDate
WHERE t2.MatchDate  <= (SELECT MatchDate FROM cte3 WHERE C = (SELECT MAX(C) FROM CTE3))
AND t2.WonBy = (SELECT WonBy FROM cte3 WHERE C = (SELECT MAX(C) FROM CTE3))

Please try the different solutions for this puzzle and share it via comment...

Greenplum is a based on MVCC architecture that means user’s action like UPDATE will insert a new record in a database.
Greenplum Data warehouse can manage billions of data, but it doesn’t mean that user can generate or UPDATE random data set.
Periodically, The Greenplum DBA should check the size of database schemas and their appropriate usage.

In this post, I shared different scripts to check the size of Greenplum Database Schemas.

Option 1:

select *
from gp_toolkit.gp_size_of_schema_disk;

Option 2:

select
	schemaname
	,round(sum(pg_total_relation_size(schemaname||'.'||tablename))) SchemaSize
from pg_tables group by 1;

Option 3:

SELECT
	schema_name
	,pg_size_pretty(sum(table_size)::bigint)
FROM
(
	SELECT pg_catalog.pg_namespace.nspname as schema_name,
	pg_relation_size(pg_catalog.pg_class.oid) as table_size
	FROM pg_catalog.pg_class
	JOIN pg_catalog.pg_namespace ON relnamespace = pg_catalog.pg_namespace.oid
) t
GROUP BY schema_name
ORDER BY schema_name;