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	<title>Initcap &#8211; Database Research &amp; Development</title>
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		<title>SQL Puzzle: SQL Advance Query – Create a function to get the string in InitCap Format</title>
		<link>https://www.dbrnd.com/2017/11/sql-puzzle-create-a-function-to-get-the-string-in-initcap-format/</link>
					<comments>https://www.dbrnd.com/2017/11/sql-puzzle-create-a-function-to-get-the-string-in-initcap-format/#comments</comments>
		
		<dc:creator><![CDATA[Anvesh Patel]]></dc:creator>
		<pubDate>Mon, 27 Nov 2017 16:16:46 +0000</pubDate>
				<category><![CDATA[SQL Puzzle]]></category>
		<category><![CDATA[Anvesh Patel]]></category>
		<category><![CDATA[database]]></category>
		<category><![CDATA[database research and development]]></category>
		<category><![CDATA[dbrnd]]></category>
		<category><![CDATA[Initcap]]></category>
		<category><![CDATA[SQL Advance Query]]></category>
		<category><![CDATA[SQL Interview]]></category>
		<category><![CDATA[SQL Problem]]></category>
		<category><![CDATA[SQL Programming]]></category>
		<category><![CDATA[SQL Query]]></category>
		<category><![CDATA[SQL Tips and Tricks]]></category>
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					<description><![CDATA[Check the below sample function execution and expected output to get the given string data in InitCap format. Sample function execution: [crayon-6aa4ac7745e2c860572694/] Expected Output: [crayon-6aa4ac7745e2f131820885/] Solution: [crayon-6aa4ac7745e30636665389/] Please try the different solution for this puzzle and share it via comment...]]></description>
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<p><strong>Sample function execution:</strong></p>
<pre class="crayon-plain-tag">SELECT [dbo].[fn_GetInitCap]('HI I AM ANVESH PATEL OWNER OF dbrnd.com') AS Result</pre> </p>
<p><strong>Expected Output:</strong></p>
<pre class="crayon-plain-tag">Result
-------------------------------------------
Hi I Am Anvesh Patel Owner Of Dbrnd.Com</pre> </p>
<p><strong>Solution:</strong></p>
<pre class="crayon-plain-tag">CREATE FUNCTION [dbo].[fn_GetInitCap] (@InputString varchar(200)) 
RETURNS VARCHAR(200)
AS
BEGIN

DECLARE @i INT
DECLARE @Char CHAR(1)
DECLARE @PrevChar CHAR(1)
DECLARE @OutputString VARCHAR(255)

SET @OutputString = LOWER(@InputString)
SET @i = 1

WHILE @i &lt;= LEN(@InputString)
BEGIN
    SET @Char = SUBSTRING(@InputString, @i, 1)
    SET @PrevChar = CASE WHEN @i = 1 THEN ' '
                         ELSE SUBSTRING(@InputString, @i - 1, 1)
                    END
    IF @PrevChar IN (' ', ';', ':', '!', '?', ',', '.', '_', '-', '/', '&amp;', '''', '(')
    BEGIN
        IF @PrevChar != '''' OR UPPER(@Char) != 'S'
			SET @OutputString = STUFF(@OutputString, @i, 1, UPPER(@Char))
    END
    SET @i = @i + 1
END
RETURN @OutputString

END
GO</pre> </p>
<p><strong><code>Please try the different solution for this puzzle and share it via comment...</code></strong></p>
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