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		<title>SQL Puzzle: SQL Advance Query &#8211; Partition Employee Table in Three parts</title>
		<link>https://www.dbrnd.com/2017/10/sql-puzzle-sql-advance-query-partition-employee-table-in-three-parts-ntile/</link>
					<comments>https://www.dbrnd.com/2017/10/sql-puzzle-sql-advance-query-partition-employee-table-in-three-parts-ntile/#comments</comments>
		
		<dc:creator><![CDATA[Anvesh Patel]]></dc:creator>
		<pubDate>Mon, 09 Oct 2017 16:16:09 +0000</pubDate>
				<category><![CDATA[SQL Puzzle]]></category>
		<category><![CDATA[Anvesh Patel]]></category>
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					<description><![CDATA[Check the below input data and expected output to divide employee table into three partitions basis on salary ranges. Input Data: [crayon-6a923ced9d0df017877830/] Expected Output: [crayon-6a923ced9d0e2359739214/] Create a table with data: [crayon-6a923ced9d0e3124399179/] Solution: Using NTILE() [crayon-6a923ced9d0e4202531633/] Please try the different solution for this puzzle and share it via comment...]]></description>
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<p><strong>Input Data:</strong></p>
<pre class="crayon-plain-tag">EmpId       EmpName    Salary
----------- ---------- -----------
1           abc        10000
2           xyz        20000
3           bcd        40000
4           rtf        30000
5           qwe        45000
6           tyu        65000
7           fgh        52000
8           dfc        35000
9           asd        45000
10          xcv        52000
11          olp        65000
12          lmj        25000
13          vbn        20000
14          efe        10000</pre> </p>
<p><strong>Expected Output:</strong></p>
<pre class="crayon-plain-tag">NumberOfPartitions   SalaryRanges              Counts
-------------------- ------------------------- -----------
1                    10000-25000               5
2                    30000-45000               5
3                    52000-65000               4</pre> </p>
<p><strong>Create a table with data:</strong></p>
<pre class="crayon-plain-tag">CREATE TABLE tbl_Emp
(
     EmpId INT
    ,EmpName VARCHAR(10)
    ,Salary INT
)
GO
 
INSERT INTO tbl_Emp
VALUES
(1,'abc',10000),
(2,'xyz',20000),
(3,'bcd',40000),
(4,'rtf',30000),
(5,'qwe',45000),
(6,'tyu',65000),
(7,'fgh',52000),
(8,'dfc',35000),
(9,'asd',45000),
(10,'xcv',52000),
(11,'olp',65000),
(12,'lmj',25000),
(13,'vbn',20000),
(14,'efe',10000)
GO</pre> </p>
<p><strong>Solution: Using NTILE()</strong></p>
<pre class="crayon-plain-tag">;WITH CTE AS
(
	SELECT
		Salary
		,NTILE(3) OVER (ORDER BY Salary) as NumberOfPartitions
	FROM tbl_Emp
)
SELECT 
	NumberOfPartitions
	,CONCAT(MIN(Salary),'-',MAX(Salary)) SalaryRanges
	,COUNT(*) Counts
FROM CTE
GROUP BY NumberOfPartitions</pre> </p>
<p><strong><code>Please try the different solution for this puzzle and share it via comment...</code></strong></p>
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