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Home 2019 May SQL Puzzle: SQL Advance Query – Report on Manager & Employee Nth level hierarchy

SQL Puzzle: SQL Advance Query – Report on Manager & Employee Nth level hierarchy

This article is half-done without your Comment! *** Please share your thoughts via Comment ***

Check the below input data and expected output to prepare the report on Manager -> Employee Nth level hierarchy basis on the ManagerID column.

Input Data:

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EmpID EmpName ManagerID
----------- ---------- -----------
1 Anvesh NULL
2 Neevan NULL
3 Mukesh 1
4 Rajesh 3
5 Nupur 2
6 Roy 5
7 Martin 6
8 Manish 1
9 Eric 2
10 Purv 9

Expected Output:

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EmpName Hierarchy FullHierarchyName
---------- --------- --------------------------
Anvesh 1 Anvesh.
Manish 8 Anvesh..Manish.
Mukesh 3 Anvesh..Mukesh.
Rajesh 4 Anvesh..Mukesh..Rajesh.
Neevan 2 Neevan.
Eric 9 Neevan..Eric.
Purv 10 Neevan..Eric..Purv.
Nupur 5 Neevan..Nupur.
Roy 6 Neevan..Nupur..Roy.
Martin 7 Neevan..Nupur..Roy..Martin.

Create a table with sample data:

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CREATE TABLE Employees
(
EmpID INT
,EmpName VARCHAR(10)
,ManagerID INT
)
INSERT INTO Employees
VALUES
(1,'Anvesh',NULL)
,(2,'Neevan',NULL)
,(3,'Mukesh',1)
,(4,'Rajesh',3)
,(5,'Nupur',2)
,(6,'Roy',5)
,(7,'Martin',6)
,(8,'Manish',1)
,(9,'Eric',2)
,(10,'Purv',9)

Solution:

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;WITH CTE(EmpName , EmpId, Level,FullHierarchyName) AS (
Select E.EmpName, E.EmpID, 0 Level
,Cast(E.EmpName+'.' as Varchar(MAX)) FullHierarchyName
From Employees E Where E.ManagerID IS NULL
UNION ALL
Select E.EmpName, E.EmpID, c.Level + 1 , c.FullHierarchyName+'.'+E.EmpName+'.' FullHierarchyName
From Employees E INNER JOIN CTE c on c.EmpID = e.ManagerID
)
SELECT H.EmpName ,CAST(H.EmpID AS VARCHAR(2)) Hierarchy , FullHierarchyName FROM CTE H
ORDER BY H.FullHierarchyName

Please try the different solution for this puzzle and share it via comment...

May 6, 2019Anvesh Patel
SQL Server Interview: How to remove New Line Character from a string?PostgreSQL: How to remove accents (diacritic signs) from lexemes
Comments: 1
  1. koustav
    October 30, 2019 at 10:17 am

    select * from
    (select empname as EmpName,empid as Hierarchy ,empname as FullHierarchyName from Employees where empname not in(select emp1.empname from Employees emp1,Employees emp2
    where emp1.managerid=emp2.empid)
    union all

    select emp1.empname,emp1.empid,emp3.empname ||’..’||emp2.empname||’..’||emp1.empname FullHierarchyName from Employees emp1,Employees emp2,Employees emp3
    where emp1.managerid=emp2.empid
    and emp2.managerid=emp3.empid
    union
    select emp1.empname, emp1.empid,emp2.empname||’..’||emp1.empname FullHierarchyName from Employees emp1,Employees emp2
    where emp1.managerid=emp2.empid and emp1.empname not in(select emp1.empname from Employees emp1,Employees emp2,Employees emp3
    where emp1.managerid=emp2.empid
    and emp2.managerid=emp3.empid )

    )T1
    order by 3

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Anvesh Patel
Anvesh Patel

Database Engineer

May 6, 2019 1 Comment SQL PuzzleAnvesh Patel, database, database research and development, dbrnd, hierarchy, SQL Advance Query, SQL Interview, SQL Problem, SQL Programming, SQL Puzzle, SQL Query, SQL Tips and Tricks
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I'm Anvesh Patel, a Database Engineer certified by Oracle and IBM. I'm working as a Database Architect, Database Optimizer, Database Administrator, Database Developer. Providing the best articles and solutions for different problems in the best manner through my blogs is my passion. I have more than six years of experience with various RDBMS products like MSSQL Server, PostgreSQL, MySQL, Greenplum and currently learning and doing research on BIGData and NoSQL technology. -- Hyderabad, India.

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