Database Research & Development

  • Home
  • NoSQL
    • NoSQL
    • Cassandra
  • Databases
    • Database Theory
    • Database Designing
    • SQL Server Coding Standards
    • SQL Server
    • PostgreSQL
    • MySQL
    • Greenplum
    • Linux
  • Interviews
    • SQL Server Interviews
    • MySQL Interviews
    • SQL Puzzles
  • DBA Scripts
    • SQL Server DBA Scripts
    • PostgreSQL DBA Scripts
    • MySQL DBA Scripts
    • Greenplum DBA Scripts
  • Home
  • Blog Archives !
  • (: Laugh@dbrnd :)
  • Contact Me !
sqlserverinterviews
Home 2017 August SQL Puzzle: SQL Advance Query – Create comma separated aggregation for Common schedules

SQL Puzzle: SQL Advance Query – Create comma separated aggregation for Common schedules

This article is half-done without your Comment! *** Please share your thoughts via Comment ***

Check the below input data and expected output to make the comma separated week aggregation for common schedules.

Input Data:

1
2
3
4
5
6
7
8
ScheduleID StartDate EndDate WeekID
----------- ---------- ---------- ------
1 2017-01-08 2017-01-09 1
1 2017-01-08 2017-01-09 2
2 2017-02-08 2017-02-09 4
3 2017-04-08 2017-05-08 6
3 2017-04-08 2017-05-08 7
4 2017-02-10 2017-04-09 3

Expected Output:

1
2
3
4
5
6
ScheduleID StartDate EndDate Weeks
----------- ---------- ---------- -------
4 2017-02-10 2017-04-09 3
3 2017-04-08 2017-05-08 6, 7
2 2017-02-08 2017-02-09 4
1 2017-01-08 2017-01-09 1, 2

Create a table with sample data:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
CREATE TABLE Schedules
(
ScheduleID INT
,StartDate DATE
,EndDate DATE
,WeekID VARCHAR(2)
)
GO
INSERT INTO Schedules
VALUES
(1,'2017-01-08','2017-01-09',1)
,(1,'2017-01-08','2017-01-09',2)
,(2,'2017-02-08','2017-02-09',4)
,(3,'2017-04-08','2017-05-08',6)
,(3,'2017-04-08','2017-05-08',7)
,(4,'2017-02-10','2017-04-09',3)
GO

Solution:

1
2
3
4
5
6
7
8
9
10
SELECT ScheduleID,StartDate, EndDate,
STUFF(( SELECT ', ' + t1.WeekID
FROM Schedules t1
WHERE s.ScheduleID = t1.ScheduleID
AND s.StartDate = t1.StartDate
AND s.EndDate = t1.EndDate
FOR XML PATH('')), 1, 1, '') Weeks
FROM Schedules s
GROUP BY ScheduleID,StartDate,EndDate
ORDER BY ScheduleID DESC

Please try the different solution for this puzzle and share it via comment...

Aug 23, 2017Anvesh Patel
SQL Puzzle: SQL Advance Query - Find the Start - End Range for the GapSQL Puzzle: SQL Advance Query - Generate report on Start - End time basis on Corresponded IDs
Comments: 2
  1. iwdw
    August 26, 2017 at 5:30 am

    Is it really necessary to use a subquery for something that simple….?

    select id,
    start_date,
    end_date,
    string_agg(week::text,’,’) as week
    from schedules
    group by id, start_date, end_date
    order by id desc;

    ReplyCancel
  2. Yogesh Shinde
    September 27, 2017 at 4:25 am

    You can do with COALESCE or XML.

    ReplyCancel

Leave a Reply to Yogesh Shinde Cancel reply

CAPTCHA
Refresh

*

Anvesh Patel
Anvesh Patel

Database Engineer

August 23, 2017 2 Comments SQL PuzzleAnvesh Patel, database, database research and development, dbrnd, Schedules, SQL Advance Query, SQL Interview, SQL Problem, SQL Programming, SQL Puzzle, SQL Query, SQL Tips and Tricks
About Me!

I'm Anvesh Patel, a Database Engineer certified by Oracle and IBM. I'm working as a Database Architect, Database Optimizer, Database Administrator, Database Developer. Providing the best articles and solutions for different problems in the best manner through my blogs is my passion. I have more than six years of experience with various RDBMS products like MSSQL Server, PostgreSQL, MySQL, Greenplum and currently learning and doing research on BIGData and NoSQL technology. -- Hyderabad, India.

About DBRND !

dbrnd

This is a personal blog (www.dbrnd.com).

Any views or opinions represented in this blog are personal and belong solely to the blog owner and do not represent those of people, institutions or organizations that the owner may or may not be associated with in professional or personal capacity, unless explicitly stated.

Feel free to challenge me, disagree with me, or tell me I’m completely nuts in the comments section of each blog entry, but I reserve the right to delete any comment for any reason whatsoever (abusive, profane, rude, or anonymous comments) - so keep it polite.

The content of this website is protected by copyright. No portion of this website may be copied or replicated in any form without the written consent of the website owner.

Recent Comments !
  • Anvesh Patel { Sure will do... } – May 27, 12:43 PM
  • Anvesh Patel { Great... } – May 27, 12:41 PM
  • Anvesh Patel { Great... } – May 27, 12:39 PM
  • Anvesh Patel { Great... } – May 27, 12:36 PM
  • Anvesh Patel { Great... } – May 27, 12:28 PM
  • Anvesh Patel { Great... } – May 27, 12:27 PM
  • Anvesh Patel { Great... } – May 27, 12:16 PM
  • Older »
Follow Me !
  • facebook
  • linkedin
  • twitter
  • youtube
  • google
  • flickr
© 2015 – 2019 All rights reserved. Database Research & Development (dbrnd.com)
Posting....