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Home 2017 November SQL Puzzle: SQL Advance Query – Find the count of Lowercase, Uppercase, Special Characters

SQL Puzzle: SQL Advance Query – Find the count of Lowercase, Uppercase, Special Characters

This article is half-done without your Comment! *** Please share your thoughts via Comment ***

Check the below input string and expected output for counting the total Lowercase, Uppercase and Other Characters (Including SPACE) in the given string.

Input String:

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'I am Anvesh Patel, owner @str DBRND.COM'

Expected Output:

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UpperCase_Count LowerCase_Count OtherCharacter_Count
--------------- --------------- --------------------
11 19 9

Solution:

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DECLARE @str AS VARCHAR(100) = 'I am Anvesh Patel, owner @str DBRND.COM'
SELECT
SUM(CASE WHEN ASCII(string) BETWEEN 65 AND 90 THEN 1 ELSE 0 END) as UpperCase_Count
,SUM(CASE WHEN ASCII(string) BETWEEN 97 AND 122 THEN 1 ELSE 0 END) as LowerCase_Count
,SUM(CASE WHEN (( ASCII(string) NOT BETWEEN 97 AND 122 ) AND ( ASCII(string) NOT BETWEEN 65 AND 90 )) THEN 1 ELSE 0 END) as OtherCharacter_Count
FROM
(
SELECT
DISTINCT Number
,SUBSTRING(@str,Number,1) as string
FROM Master..spt_Values
WHERE Number > 0 and number <= LEN(@str)
)as t

Please try the different solution for this puzzle and share it via comment...

Nov 21, 2017Anvesh Patel
SQL Puzzle: SQL Advance Query - Find the Sum of privious values without using a self-joinSQL Puzzle: SQL Advance Query - Delete duplicate without using RANK, PARTITION, ROW NUMBER
Comments: 1
  1. Dpan
    April 23, 2019 at 11:43 am

    DECLARE @str AS VARCHAR(100) = ‘I am Anvesh Patel, owner @str DBRND.COM’,@i as int=1,@lengthOfstr as int,@getString as nvarchar(max),
    @sumOfUpper as int,@sumOfLower as int,@sumOfOtherChar as int
    set @lengthOfstr=LEN(@str);set @sumOfUpper=0;set @sumOfLower=0;set @sumOfOtherChar=0;
    while (@i<=@lengthOfstr)
    begin
    select @getString= SUBSTRING(@str,@i,1)
    select @sumOfUpper+=case when ASCII(@getString) between 65 and 90 then 1 else 0 end;
    select @sumOfLower+=case when ASCII(@getString) between 97 and 122 then 1 else 0 end;
    select @sumOfOtherChar+=case when (ASCII(@getString) not between 65 and 90 and ASCII(@getString) not between 97 and 122) then 1 else 0 end;
    set @i=@i+1;

    end
    print (Concat('Upper char–', @sumOfUpper))
    print (Concat('Lower char–', @sumOfLower))
    print (Concat('Other char–', @sumOfOtherChar))

    ReplyCancel

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Anvesh Patel
Anvesh Patel

Database Engineer

November 21, 2017 1 Comment SQL PuzzleAnvesh Patel, database, database research and development, dbrnd, Lowercase, SQL Advance Query, SQL Interview, SQL Problem, SQL Programming, SQL Puzzle, SQL Query, SQL Tips and Tricks, string, Uppercase
About Me!

I'm Anvesh Patel, a Database Engineer certified by Oracle and IBM. I'm working as a Database Architect, Database Optimizer, Database Administrator, Database Developer. Providing the best articles and solutions for different problems in the best manner through my blogs is my passion. I have more than six years of experience with various RDBMS products like MSSQL Server, PostgreSQL, MySQL, Greenplum and currently learning and doing research on BIGData and NoSQL technology. -- Hyderabad, India.

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