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Home 2018 March SQL Puzzle: SQL Advance Query – Generate a Random number in the range of Fifty

SQL Puzzle: SQL Advance Query – Generate a Random number in the range of Fifty

This article is half-done without your Comment! *** Please share your thoughts via Comment ***

Most of you guys are already using NEWID() for forming a random number in SQL Server.

Freshly, I got a new SQL Puzzle which is small and sweet.

As an interviewer, I can ask one line question like “Can you please generate random number column which should be between 0 and 50”

Very reasonable and small question right, believe me, the answer is also in one line.

Check the below solution, and try it your self.

Solution:

1
SELECT ABS(CHECKSUM(NewId())) % 50 AS RandomNumber

Please try the different solution for this puzzle and share it via comment...

Mar 2, 2018Anvesh Patel
SQL Puzzle: SQL Advance Query – Count total number of Working Days between Two DatesSQL Server: Create Full Text Search Index, Use CONTAINS for pattern matching
Comments: 2
  1. VINUTNA
    May 22, 2018 at 11:26 am

    select round(50 * rand(),0) as random_number

    ReplyCancel
  2. HIC
    May 3, 2019 at 8:23 am

    PL/SQL:
    select round(dbms_random.value * 50) from dual;

    ReplyCancel

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Anvesh Patel
Anvesh Patel

Database Engineer

March 2, 2018 2 Comments SQL PuzzleAnvesh Patel, database, database research and development, dbrnd, SQL Advance Query, SQL Interview, SQL Problem, SQL Programming, SQL Puzzle, SQL Query, SQL Tips and Tricks
About Me!

I'm Anvesh Patel, a Database Engineer certified by Oracle and IBM. I'm working as a Database Architect, Database Optimizer, Database Administrator, Database Developer. Providing the best articles and solutions for different problems in the best manner through my blogs is my passion. I have more than six years of experience with various RDBMS products like MSSQL Server, PostgreSQL, MySQL, Greenplum and currently learning and doing research on BIGData and NoSQL technology. -- Hyderabad, India.

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